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4.9x^2+340x-23=0
a = 4.9; b = 340; c = -23;
Δ = b2-4ac
Δ = 3402-4·4.9·(-23)
Δ = 116050.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(340)-\sqrt{116050.8}}{2*4.9}=\frac{-340-\sqrt{116050.8}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(340)+\sqrt{116050.8}}{2*4.9}=\frac{-340+\sqrt{116050.8}}{9.8} $
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